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fd5cde525c
fix for #1934 This fixes a race condition between Stack thread and DL PDU processing that lead to updates of the RLC buffer that are undetected by the BSR routine. What happens is that in a UL SCH PDU all outstanding data is transmitted and and a LBSR with all zero buffers is sent. 14:39:47.327301 [MAC ] [D] [ 3793] BSR: LCID=3 old_buffer=59 14:39:47.330600 [MAC ] [I] [ 3793] UL LCID=3 len=58 LBSR: b=0 0 0 0 Note that "old_buffer" isn't set to zero here. At the same time (same TTI), the MAC PDU processing thread handles DL-SCH PDUs that may generate new UL PDUs: 14:39:47.330749 [RLC ] [I] DRB1 Tx SDU (54 B, tx_sdu_queue_len=1) 14:39:47.330762 [RLC ] [I] DRB1 Tx SDU (54 B, tx_sdu_queue_len=2) 14:39:47.330775 [RLC ] [I] DRB1 Tx SDU (54 B, tx_sdu_queue_len=3) .. Those PDUs are "new data" since the previous buffer state was zero. Here is the race now between the threads, at the end of the bsr::step() function old_buffer of each LCG is updated with the previous new_buffer, so the buffer state of LCG=2 is now 59. Now MAC starts the next TTI: 14:39:47.331910 [MAC ] [D] [ 3794] Running MAC tti=3794 14:39:47.331928 [MAC ] [D] [ 3794] Update Bj: lcid=0, Bj=0 14:39:47.331934 [MAC ] [D] [ 3794] Update Bj: lcid=1, Bj=0 14:39:47.331938 [MAC ] [D] [ 3794] Update Bj: lcid=2, Bj=0 14:39:47.331941 [MAC ] [D] [ 3794] Update Bj: lcid=3, Bj=-1752 14:39:47.331951 [MAC ] [D] [ 3794] BSR: LCID=0 update new buffer=0 14:39:47.331960 [MAC ] [D] [ 3794] BSR: LCID=1 update new buffer=0 14:39:47.331964 [MAC ] [D] [ 3794] BSR: LCID=2 update new buffer=0 14:39:47.331971 [MAC ] [D] [ 3794] BSR: LCID=3 update new buffer=335 14:39:47.331976 [MAC ] [D] [ 3794] BSR: check_new_data() -> get_buffer_state_lcg(0)=0 14:39:47.331980 [MAC ] [D] [ 3794] BSR: check_new_data() -> get_buffer_state_lcg(1)=0 14:39:47.331984 [MAC ] [D] [ 3794] BSR: check_new_data() -> get_buffer_state_lcg(2)=59 14:39:47.331988 [MAC ] [D] [ 3794] BSR: check_new_data() -> get_buffer_state_lcg(3)=0 14:39:47.331993 [MAC ] [D] [ 3794] BSR: LCID=0 old_buffer=0 14:39:47.332000 [MAC ] [D] [ 3794] BSR: LCID=1 old_buffer=0 14:39:47.332003 [MAC ] [D] [ 3794] BSR: LCID=2 old_buffer=0 14:39:47.332007 [MAC ] [D] [ 3794] BSR: LCID=3 old_buffer=335 And since the buffer state of LCG=2 isn't zero, the new data for LCID=3 of that LCG is considered. So effectivly, the BSR missed the "empty" buffer state for a fraction of time and doesn't consider the outgoing data generated in the same TTI as new. It therefore doesn't transmit a BSR. in which a BSR wasn't |
4 years ago | |
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mac | 4 years ago | |
rrc | 4 years ago | |
upper | 4 years ago | |
ue_stack_base.h | 5 years ago | |
ue_stack_lte.h | 4 years ago | |
ue_stack_nr.h | 5 years ago |